Analytical Mech Homework Solutions 24

Analytical Mech Homework Solutions 24 - Fr = mg + mk mkd k...

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cos rm mk mkd k Fm g x m g t M mM m M =+ ++ m + For the block to just begin to leave the bottom of the box at the top of the vertical oscillations, 0 r F = at m x d = − : 0 mkd mg M m =− + () gM m d k + = 3.9 cos t d xeA t γ ω φ () () sin cos tt dd d dx eA t t dt γγ ωφ −− maxima at ()() 0s i n c o s d dt dx − + == tan d d t −= thus the condition of relative maximum occurs every time that t increases by 2 d π : 1 2 ii d + For the i th maximum: ( ) cos i t id t i = 1 2 11 cos t i i x t e γω + x = 2 1 T i i x ee x + 3.10 (a) 1 3 2 c s m 22 25 k s m D 222 16 d s ωω 2 =−= D
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This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.

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