3.16(b) 22dQωγγγ−D==21LC=D, 2RL=222141422RLCLLRRCL−Q−(c) 2LRCQRR===DD3.17sinImitextFF tFeand ()x tis the imaginary part of the solution to: mxcxkxF e++=D±±±i.e. xtImsinAeAtωφφ−−where, as derived in the text, 1222FAkmcωω=−+Dand 2tanγω=−D3.18Using the hint, , where RetextFFβ=Deiα=, and x(t)is the real part of the solution to: mxtcxkxF eD±. Assuming a solution of the form: tixAe−=2iFmckxxeAββ++ =D2cFmimmcickiAossinαω−−−
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