Analytical Mech Homework Solutions 30

Analytical Mech Homework Solutions 30 - 3.22 In steady...

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3.22 In steady state, ( ) ( ) n i n t n n A e x t ω φ = ( ) 1 2 2 2 2 2 2 2 2 4 n n F m A n n ω ω γ ω = + D Now 4 n F n F π = , . . . and D 1,3,5, n = 3 ω ω = D 100 2 Q ω γ = D so 2 2 9 40,000 ω γ ( ) 1 1 2 2 2 2 2 2 4 1 9 9 4 40000 F A m π ω ω ω ω = + D 1 2 2 F A m πω D ( ) 3 1 2 2 2 2 2 2 4 1 3 9 9 9 4 200 F A m π ω ω ω = + D 3 2 400 27 F A m πω D ( ) ( ) 5 1 2 2 2 2 2 2 4 1 5 3 9 25 4 5 200 F A m π ω ω ω ω = + D 5 2 20 F A m πω D i.e., A : A : 1 : 29.6 : 0.1 1 3 5 A = 3.23 (a) Thus 2 0 x
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