Analytical Mech Homework Solutions 37

Analytical Mech Homework Solutions 37 - h= re 1 2 2re v 2z...

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2 2 2 1 22 ee e rr hr g =− D z v ( ) , e hz r ± 2 2 1 z e v gr D h From Appendix D, () 2 1 2 11 28 xx x + =+ − + 24 222 4 zz e vv h gg r =−+ + + DD 1 e h r  ≈+   From Example 2.3.2, 2 2 g D v h = 1 2 1 2 e v gr D And with 1 x x −≈ + , 1 e h r 4.7 For a point on the rim measured from the center of the wheel: ˆˆ cos sin ri b j b θ K vt t b θω == D , so sin cos v j v K ² Relative to the ground, ( ) 1s i n c o s v j v vi =− − K For a particle of mud leaving the rim: sin yb D and cos y = − So cos yy g t v g t =−= and 2 1 sin cos 2 v t g t D At maximum height, 0 v y = : cos v g t D 2 cos 1 cos sin cos 2 v g hb  
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This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.

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