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Analytical Mech Homework Solutions 38

# Analytical Mech Homework Solutions 38 - sin = gb v2 cos 2 =...

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2 sin gb v θ = − D 4 2 2 2 4 cos 1 sin v g b v θ θ = = D D 2 2 4 2 2 2 2 max 2 2 2 2 2 gb v g b gb v h v gv v = + = + D D D D D 2 g Measured from the ground, 2 2 max 2 2 2 gb v h b v g = + + D D The mud leaves the wheel at 1 2 sin gb v θ = D 4.8 cos x R φ = and ( ) cos x x v t v t α = = D D so co R t s cos v φ α = D sin y R φ = and ( ) 2 2 1 1 sin 2 2 y v t gt v t g α = = D D y t α φ ( ) 2 cos 1 cos sin sin cos 2 cos R R R v g v v φ φ φ α α α = D D D 2 2 2 cos sin tan cos 2 cos gR v φ φ α φ α = D ( ) ( ) 2 2 2 2 2 2 cos 2 cos tan cos sin sin cos cos sin cos cos v v R g g α α α φ φ α φ α φ φ = = D D φ From Appendix B, sin ( ) sin cos cos sin θ φ θ φ θ + = + φ ( ) 2 2 2 cos sin cos v R g α α φ φ = D R is a maximum for ( ) ( 2 2 2 0 sin sin cos cos cos dR v d g ) α α φ α α φ α φ = = +
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