Analytical Mech Homework Solutions 45

Analytical Mech Homework Solutions 45 - 2 x z 8x z 2 + g 3g...

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2 max 2 28 3 xz x gg γ =− + DD ±± For sin zv α = ± and 2 2 2s i n v = D ± ± ) y x : 23 max 2 sin 2 4 sin 2 sin 3 vv x + 4.16 ( cos xA t ω = + , ( ) sin t ωα = −+ ± my ± from 0 x = D ± , 0 = 2 from x A = D , cos x At = with , ( ) cos yB t β = + , ( ) sin yB t ωβ + ± 22 111 kB ky =+ 2 4 yA = D 3 = D ± and k m = : 2 1 16 B 5 B A = Then 4 5 cos AA = () 2 2 9 25 = 2 A and 3 5 sin = − Since m respectiv in 11 43 cos sin 36.9 55 −−    == =       D rectangl aximum x and y displacements are 5 cos 36.9 t D A ± and 5 A ± AB , ely, the motion takes place entirely with a e of dime and . From eqn 4.4.15, nsion 2 A 10 A 2 5 cos 6.9 D 36.9 0 36.9 βα ∆= − =− tan 2 4 ψ 2c o s tan 2 AB = = .17 D 2 2 10 3 1
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This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.

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