Analytical Mech Homework Solutions 49

Analytical Mech - z kB F = q E vB E j iv0 j v B = ix y kz kB = iyB xB j F = iqyB q E xB j y mx = Fx = qyB qB xx = y m x qB my = Fy = qE qxB = qE qB

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h x 17 ( ) FqEvB = G GG G G G ( ) ˆˆ ˆ ˆ v B ix jy kz kB iyB jxB ×= + + × = ±± ± ± ± G ( ) Fi q y Bj qEx B =+ − x mx F qyB = = ± qB x xy m −= D y y qB my F qE qxB qE qB x m ==− =− + D ± ±    y ˆ kB ˆ jE x z 0 ˆ iv 22 qE qBx qB eE eBx eB yy mm m =− − = −+ − DD y 2 eE m x ω += −+ D ± , eB m = () 2 1 cos eE yx A m t ωθ =− + + + sin yA t + D ± 0 y = D ± , so 0 θ = D 0 y = D , so 2 1 eE Ax m + D ± 1c o s ya t , 2 1 eE ax m + D ± o s qB x x y x a m t ωω =+ =− =− D ± ± cos x xaa t =− + D sin x xa t a t + D ± sin x at b t , bx a D ± 0 z mz F == 4 0 zz tz =+= ± .21 2 1 b mv mqh mg s + y b ( ) 2 2 vg bh 2 co r mv Fm g b = R
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This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.

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