Analytical Mech Homework Solutions 52

Analytical Mech Homework Solutions 52 - g g = g A = g i j...

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ˆˆ 10 g ggAg j =− = − D G GG i For small oscillations of a simple pendulum: 1 2 g π = T 2 2 1.005 10 g gg  =+ =   g 11 2 1.995 1.005 ππ == T 5.5 (a) f mg µ =− is the frictional force acting on the b x, so G G o 0 f mA ma −= G ( a G is the acceleration of the box relative to the truck. See Equation 5.1.4b.) Now, f G the only real force acting horizontally, so the acceration relative to the road is 0 A G f G (b) 3 f mg g ag mm = − = (For + in the direction of the moving truck, the – indicates that friction opposes the forward sliding of the box.) 2 g
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