ˆˆ10gggAgj′=− = −DGGGiFor small oscillations of a simple pendulum: 12gπ=′T221.00510ggg′=+=g1121.9951.005ππ==T5.5(a) fmgµ=−is the frictional force acting on the b x, soGGo0fmAma′−=G(a′Gis the acceleration of the box relative to the truck. See Equation 5.1.4b.) Now, fGthe only real force acting horizontally, so the acceration relative to the road is 0AGfG(b) 3fmggagmm−=− =−(For + in the direction of the moving truck, the – indicates that friction opposes the forward sliding of the box.) 2g
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