For raθ=, and the force to be central, try nbt=() ( )222 222 221nnfmabntabnnt−−=+−For a central field … ()0f=+−=013n=13bt=6.14(a) Calculating the potential energy 2354dvafrkdrrr−==−+Thus, 22424aVkrr=−+The total energy is … 222221211990224kkETVv kaaa a=+=−+=−=DDDIts angular momentum is … 2492klavconstantr2====D±Its KE is … 22241112drdrlTrrrrddθθ=+ =+ =+±±±rThe energy equation of the orbit is … 22420drlaTVrkdrr+==+−+4r2229244drkarkr=+−+4ror 219drardLetting cosφ=then sindadrSo 219dd=13∴=7
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This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.