Analytical Mech Homework Solutions 70

Analytical Mech - 1 r = a cos r = a = 0 3 3(b at = r 0 the origin of the force To find how long it takes 2 av v l = 2= = 1 1 r a 2 cos 2 a cos 2 3

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Thus 1 cos 3 ra θ = () @0 == D (b) at 3 2 π = the origin of the force. To find how long it takes … 0 r 2 22 2 11 cos cos 33 av v l r aa = DD ± 2 1 cos 3 a dt d v θθ = D 3 00 13 3 cos cos 34 Tdd vv ππ a v φφ ∫∫ = D Since 1 2 2 9 2 k v a  =   D 2 2 32 2 49 4 a Ta kk (c) Since the particle falls into the center of the force v →∞ (since ) l vr const 6.15 From Example 6.5.4 … 1 2 1 1 2 c vr r = + D D Letting c v v = D V we have 1 2 1 2 1 r r = + D V So: 2 2 1 21 2 rr dV dr V r r   =− +  1 Thus 2 1 1 1 11 1 1 2 1 1 2 1 dV V dr r r r r r 
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This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.

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