Analytical Mech Homework Solutions 77

Analytical Mech Homework Solutions 77 - 6.25 f(r = 2k 4 r3...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
6.25 () 35 24 k fr rr ε =+ From equation 6.13.7, the condition for stability is 0 3 a fa f a + < 0 3 ka k aa εε  −−+ + <   0 33 k −+< 2 k a < 1 2 a k > 6.26 (a) 2 br e k r =− 23 2 22 br br be k e k b r r = + From equation 6.13.7, the condition for stability is 0 3 a + < 2 0 3 ba ba ea e kk b a −− −+ + < 2 0 ba ba eb e < 1 b a < 1 a b < (b) 3 k r 4 3 k r = 34 3 0 ak a k += + = Since 3 a f af + a is not less than zero, the orbit is not stable.
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Ask a homework question - tutors are online