Analytical Mech Homework Solutions 80

Analytical Mech Homework Solutions 80 - dV k 3k k 2 =+ = 4...

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() 2 24 4 3 3 dV k k k fr r dr r r r ε =− = + = + 2 35 5 21 2 2 6 kk k r rr r + 2 2 26 3 fa r ar  +  +  From equation 6.14.3, 1 2 3 a ψπ  =+   1 22 2 63 32 33 π ++ = +− For 2 5 R R =∆ , 4000 R mi = , 13 R mi = ( ) 42 2 4000 13 2.08 10 5 mi == × For , rR 27 1.6 10 rm 2 i 1.0039 180.7 D 6.30 2 2 1 2 rel VE c r + D 2 2 dV k k k E dr r m c r r + + D 2 1 1 E c r + + D 2 2 1 1 k E r m cr DD 2 k 13 E c r + D 2 2 1 1 1 k E mc a k a E a D D 2 31 2 3 1 1 EE a a a k E a − + += D 3 18
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This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.

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