Analytical Mech Homework Solutions 82

Analytical Mech Homework Solutions 82 - 1 2 1 2 sin = 2 RV...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
( ) ( ) 1 2 2 2 2 2 2 2 1 sin sin 2 sin 1 RV RV θ ε φ φ ε = + Again from Example 6.5.3 … ( ) 1 2 2 2 2 1 si V RV R ε φ = + n 2 ( ) 2 2 2 2 1 sin 2 sin RV RV ε φ φ = + ( ) ( ) 1 2 2 2 2 2 2 1 sin sin sin RV RV θ φ ε = φ 2 1 sin sin cos RV θ φ φ ε = 2 2 2 cos sin 1 sin sin cos RV RV θ φ θ φ φ = 2 2 cot tan sin 2 RV θ φ φ = 1 2 2 cot tan csc2 RV θ φ φ = For , 0.5 V = 4 R = , : 30 φ = D ( ) 1 2 2 cot tan30 csc60 4 .5 θ = D D ( ) 1 1 1 2 cot cot 3 3 3 2 = = 30 θ = − D 6.32 The picture at left shows the orbital transfer and the position of the two satellites at the moment the transfer is initiated.
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern