Analytical Mech Homework Solutions 86

Analytical Mech Homework Solutions 86 - vg = 7.4 v 1+ v mv...

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1 g v v γ =− + D G G 7.4 Momentum is conserved: 2 blk v mv m Mv  =+   D D 1 2 blk vv = D m M = 22 2 11 1 2 2 2 if TT m v m M    −= +       DD D 2 2 1 1 24 mv M m 4 D 3 44 i T v 0 60 o θ v 0 / 2 7.5 At the top of the trajectory: ˆˆ cos60 2 v vi v i == D D D G Momentum is conserved: 2 2 2 vm v m im j v G 2 2 v vj D D G Direction: 1 2 tan 26.6 v v θ D D D below the horizontal. Speed: 1 2 2 2 2 1.118 2 v = D v 7.6 When a ball reaches the floor, 2 1 2 mv mgh = . As a result of the bounce, v v ε = . The height of the first bounce: 2 1 2 mgh mv = 2 2 hh gg == = Similarly, the height of the second bounce,
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This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.

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