Analytical Mech Homework Solutions 88

Analytical Mech Homework Solutions 88 - 7.8 1 1 1 2 From...

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7.8 From eqn. 7.2.15, 222 11 2 2 111 ii i v m v m == + Tm v Meanwhile: () 2 2 22 1 2 12 1 2 cm mv mm mv v m v v m µ +  += +  +  G G G G 2 2 1 21 2 1 2 1 2 1 2 mv mv vv mmv v vv m  =+ + + +  G GG G Therefore, cm v v 7.9 From Prob. 7.8, cm v v and since QTT =− cm cm = : Qv v From eqn. 7.5.4, v v ε = 1 1 2 Qv 7.10 Conservation of momentum: ′′ 2 1 m v m 2 2 1 2 2 2 v v v + 2 2 Conservation of energy: 2 2 2 2 212 2 1 1 m mvv v m 2 =−+ + 2 1 2 1 10 2 vm v v m +− = 2 2 v ′ = + 2 22 2 1 1 1 2 11 1 2 T T v −= = = + 2 4
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This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.

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