Analytical Mech Homework Solutions 95

Analytical Mech Homework Solutions 95 - 1 = m1 m2 ( 2T m1 )...

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() 1 2 1 1 1 2 2 11 22 2 12 2 21 1 Tm m m T mm m Q γ = +− + Finally… 1 1 2 2 1 1 1 m m Qm m T = +    7.21 The time of flight, τ = constant—so 1 r v = but from problem 7.19 above 1 1 1 1 v rv τγ α == + +− + As an example, let v 1 1 = and we have r 1 = 1 = pp scattering 2 2 1 3 3 γγ =++ r 2 = p – D 2 3 1 15 5 r 4 = p – He 2 4 1 143 13 r 12 = p – C Below is a polar plot of these four curves. 7.22 From eqn. 7.7.6, ug FF m vv m −= + ±± since v = constant, 0 v = ± mzv λ
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This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.

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