9()12222211115321MaMgaαβαβπααβ−+ + −=−−DT(a) 22111121TT=≈D−to 1storderin(b) 10mg=1Mkg=1.27am=5bcm=0.01=0.0394=110.999212T≈−=DT(actually 0.9994 using complete expression) 8.10The period of the “seconds” pendulum is 2IMgl==TsThe period of the modified pendulum is 20InMgln′′′′−Twhere I′, M′, lrefer to parameters of pendulum with m attached and ′is the number of seconds in a day. n(246060=××)2mIIml′=+mMlmllM+′ =where lis the distance of the attached mass from the pivot point. mmSo 22201mm2ImlInMglMlmlππ−′+−==+g
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This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.