Analytical Mech Homework Solutions 140

Analytical Mech Homework Solutions 140 - L = mg z L L = =...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
0 LL xy ∂∂ == , L mg z =− From equations 10.4.5 … 0 ii Ld L qd tq  −=   ± , 0 mx = ±± mx const = ± , 0 my = my const = ± mz mg 10.3 Choosing generalized coordinate x as linear displacement down the inclined plane (See Figure 8.6.1), for rolling without slipping … x a ω = ± 2 22 2 2 1111 2 7 2222 5 1 0 x T mx I mx ma mx a =+=+ = ± 2 ± For V at the initial position of the sphere, 0 = Vm sin g x θ 2 7 sin 10 LTV m x m g x =−= + ± 7 5 L mx x = ± ± , 7 5 dL mx dt x = ± sin L mg x = 7 sin 5 mx mg = 5 sin 7 xg = From equations 8.6.11 - 8.6.13 … 5 sin 7 cm = 10.4 (a) For x the distance of the hanging block below the edge of the table:
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.

Ask a homework question - tutors are online