Analytical Mech Homework Solutions 141

Analytical Mech Homework Solutions 141 - 1 m mg 2 x x (b) T...

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(b) 22 1 m x m x m x 2 Tm  =+   ±± ± and 2 x xm g x m g m g x x ll =− g Vm mm LTV m g x x l ′′ =−= + + + ± g () 2 L mmx x ± ± , 2 dL dt x ± Lm mg x g x l 2 mg mmxm g x l += + 2 gm lm x x m + = + 10.5 The four masses have positions: m 1 : 12 x x + m 2 : 11 lxx 2 + m 3 : 3 + m 4 : 223 lxlx 3 +− ( ) ( ) 21 1 2 Vg m l x x + 2 m x x + + ( ) ( ) 32 2 3 42 2 3 3 ml x x ml x l x + + − + ()( 2 2 1 2 1 2 x x x + + ) ) ( 323 423 mxx mxx +−+ + −− 2 2 1 2 3 2 3 1 2 mx x m x x =−= + + −+ + 2 ( ) 2 1 2 1234 3 34 1 . 2 mxx g x mmg x mmmmg x mmc o n s + − + +−−+ t ( 2 2 1 2 1 L m x x x + ± ) ) 2 ( 1 12 mmx mmx ( 1 dt x ± ) 2 1 L gm m x ( ) 2 mmx mmx gmm ++ − =− 3
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This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.

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