Analytical Mech Homework Solutions 160

Analytical Mech Homework Solutions 160 - (b Atwoods machine...

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(b) Atwood’s machine … () 12 Vm g x m g l x =− 2 22 2 111 222 x Tm x m x I a =++ ± ±± [Includes the pulley] 2 TI p mm x xa  ==++   ± , 2 p x I a = ++ ± 2 2 2 2 p HTV mmg xm g I a =+= l 2 Hp x I p a == ± H x ± p , ( ) p ± (c) Particle sliding down a smooth inclined plane … sin g x θ 2 1 2 = ± x T p mx x ± ± , p x m = ± 2 sin 2 p m g x m x pm ± sin H mg p x ± , sin g = ± 10.28 (a) r F (,) (, ) ii i LTqq Tq t ± …note, potential energy is time dependent. V
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This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.

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