Analytical Mech Homework Solutions 171

# Analytical Mech Homework Solutions 171 - 8 Equilibrium @ =...

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8 Equilibrium @ 0 φ = 2 3 0 cos2 e GM a V r ′′≈ and 2 0 3 0 e GM a r V 2 1 3 M Im a == 0 3 0 3 e VG Mr ω ′′ M 3 0 0 2 2 3 e r T GM π 11.13 The amplitude of the symmetric component is A 1 and the amplitude of the anti-symmetric component is A 2 (See Equations 11.3.19a through 11.3.20b). [] 2 2 112 1 (0) (0) 4 Axx =+ 0 11 2 1 (0) (0) 22 A = 2 2 221 1 (0) (0) 4 =− 0 22 1 1 (0) (0) A = 12 AA = From Equation 11.3.18 the solution for x 1 is … () 0 11 cos 2 A 2 x tt t (The phase 2 δ is 180 o , which insures that 10 (0) x A = ) 0 1 2cos 22 2 A xt ωω +−  =   Letting … 1 and 2 =∆ = x tA t t
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## This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.

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