This preview shows page 1. Sign up to view the full content.
23
()
2
2
3
12
mM
KK
mm
M
m
ω
+
==
+
+
11.24
y
2
a
a
α
α
M
x
2
m
y
1
x
1
y
3
x
3
m
Select coordinates (
x
i
,
y
i
) as shown, then …
2222
2 2
1133
11
22
Tm
xyxy
M
xy
=+
+
+
+ +
±±±±
±±
The potential energy depends only on the compression (or stretching) of the two springs
connecting each
m
to
M
(hydrogen to sulfur).
Let
1
a
δ
and
2
a
be incremental changes
in the distances
a
or
and
or
. We have …
1
(1
2)
HS
→
2
a
(3
HS
2)
→
() ()
2
2
1
1
2
2
1
sin
cos
2
ax
x
yy
x
xyy
δα
α
=−
+−
=
−+−
1
3
2
3
2
3
2
1
sin
cos
2
x
y
y
x
x
y
y
=
3
()()
1
2
Vka
a
δδ
We can reduce the degrees of freedom from 6 to 3 by ignoring the two translational
modes and the rotational mode.
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.
 Fall '11
 JohnAnderson
 Energy, Potential Energy, Work

Click to edit the document details