Analytical Mech Homework Solutions 192

Analytical Mech - 29 l 2a < x

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29 () 2 (,0 ) 2 al yx l x x l l =− < < We can now determine B n 2 02 22 2 sin sin l l n l an xa n x B xd xl x ll l l l ππ  =+   ∫∫ d x Using integration tables, we obtain the result … 1 2 8 1 sin 1,3,5,. .. 2 n n Bn n π = 0 2,4,6,. .. n == Thus, the general solution is … 2 81 3 3 1 5 ( , ) cos sin cos sin cos sin ... 92 5 av t x v tx v yxt l l  =−+   5 None of the harmonics which have a node at the midpoint have been stimulated … only the odd harmonics have been excited. 11.30 By analogy with the generation of the traveling sine wave of Equation 11.6.14 from Equation 11.6.13, we get …
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This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.

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