Analytical Mech Homework Solutions 2

Analytical Mech Homework Solutions 2 - 1.3 cos = 5a 2 A B...

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1.3 2 2 22 () () ( 2) ( 2) ( 0 ) ( 3) 5 cos 51 4 4 AB a a a a a a AB a aa θ ⋅+ + == = K K 1 5 cos 53 14 =≈ ° 1.4 (a) ˆ ˆˆ Ai jk = ++ K : body diagonal K K ˆˆ ˆˆ 3 AA A i ij jk k =⋅= ⋅+ ⋅= (b) B = + K : face diagonal K 2 BB B =⋅= K (c) ˆ 111 110 ijk B =×= KK K CA (d) 11 0 32 AB ⋅− == = K K cos 90 = D 1.5 sin BB ACA C ==×= K K K sin y B CC A cos AC u = cos x u A 2 xy A uB A B C A A BA ××  =+  ×  K B A K K K K 1 u =+× A K K K 1.6 23 ˆ ˆ d d d it jt kt
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This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.

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