Analytical Mech Homework Solutions 13

Analytical Mech Homework Solutions 13 - 1 F e cx dx m 12 F...

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1 cx xdx F e dx m = D ±± () 2 1 11 2 cx cx FF xe cm cm −− =− = DD ± e 1 2 2 1 cx F cm    D ± (c) 1 cos dx x xF dx m D ± ± c x == cos F xdx cx dx m = D 2 1 sin 2 F x cx cm = D ± 1 2 2 sin F x cx cm  =   D ± 2.3 (a) () ( ) 2 2 x x cx F c xd x F x C + + D Vx (b) x cx cx x F F e d x e C c = + D D D (c) cos sin x x F F c x d x c x C c + D D D 2.4 (a) dV x k x dx Fx 2 0 1 2 x k x d x k x (b) TT () () xV x =+ D 2 1 2 T Vx kA x = D Tx (c) 2 1 2 ET k A D (d) turning points @ 1 0 1 x A 2.5 (a) 3 2 kx Fx k x A −+ so 34 2 22 0 24 x kx kx k x d x k x AA =− =−
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