(d) Vhas maximum at ()x( )0mFx→320mmkxA−=kxmxA= ±422211 124 4mkAxkAkAA=− =VIf turning points exist. (mEVx<)Turning points @ Txlet u10→21x=2211024kuEkuA−+=solving for u, we obtain 12224EkA=±−uAor 12124ExAkA−−2.6xvxxα==±223xxxx=−±±±23mmxx−2.7sinFMgθ≥2.8dxFmxmxdx±±3xbx−=±43dxbxdx−±(343Fm bxbx−−
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This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.