Analytical Mech Homework Solutions 14

Analytical Mech Homework Solutions 14 - (d V x has maximum...

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(d) V has maximum at () x ( ) 0 m Fx 3 2 0 m m kx A −= kx m x A = ± 4 22 2 11 1 24 4 m kA x kA kA A =− = V If turning points exist. ( m EVx < ) Turning points @ Tx let u 1 0 2 1 x = 2 2 11 0 24 ku Ek u A −+ = solving for u , we obtain 1 2 2 2 4 E kA       uA or 1 2 1 2 4 E xA kA 2.6 xvx x α == ± 2 23 xx x x =− ±± ± 2 3 m m x x 2 . 7 sin FM g θ 2.8 dx Fm xm x dx ± ± 3 x bx = ± 4 3 dx bx dx ± ( 34 3 F m bx bx −−
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This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.

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