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Unformatted text preview: #9.62 H0: p = 0.95 H1: p > 0.95 Decision rule: Reject H0 if z > 1.96. Test statistic Z = (phatp)/sqrt[p*(1p)/n] = (485/5000.95)/sqrt(0.95*(10.95)/500) = 2.0519 Since 2.01519 > 1.96 we reject H0 and conclude that they are exceeding their goal.#9.64 H0: u = 250 H1: u > 250 (onesided) a = 0.05 Test statistic t = (xbar  u)/(s/sqrt(n)) df = 251 = 24 Rejection region: Reject H0 when T > t(0.95, 24) = 1.711 Value of test statistic: t = (275.66  250)/(78.11/sqrt(25)) = 1.643 Since 1.643 < 1.711 we fail to reject H0 and conclude that the average patient does not pay more than $250. This was a close decision, the pvalue is 0.0567!...
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This note was uploaded on 01/05/2012 for the course 101 melissa jo taught by Professor Acc101 during the Spring '11 term at Aarhus Universitet.
 Spring '11
 acc101

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