Example of retaining wall - SD.docx - Example Design a cantiliver retaining wall for the condition shown below p 1 1 H D 2 2 C2 = 150 2= 16 kN\/m3 H =9m

Example of retaining wall - SD.docx - Example Design a...

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Example Design a cantiliver retaining wall for the condition shown below = 15 0 2 = 16 kN/m 3 H =9m 2 =20 0 P = 20kN/m 2 C 2 = 50 kN/m 2 D= 1.5m C25 1 = 34 0 steel grade 300 1 = 18kN/m 3 Requirement p H D 1 , 1 2 , 2, C 2
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- Stability analysis - Structural design o Determination of steel cut offs o Drainage provision o Structural Drawing Solution i, Tentative Design Dimension - Calculation of the thickness of the base of the stem =15 0 9m 0.80m 7m p= 20kN/m 2 2.35m 30cm t b
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H= P = 20 18 = 1.11 m The horizontal component of lateral earth pressure on the stem is Ph = h cos K a Where cos + cos 2 β ¿ cos 2 = 0.311 K a = cos Cosβ cos 2 β cos 2 ¿ Then P h = 18 * h* 0.311*Cos 15 0 When h = 1.11m , P h = 6.04kN /m 2 When h= 10.11m , P h = 55.03 kN/m 2 H 9m 10.11m t b 9m 30cm 6.04kN/m 2 t b 55.03kN/m 2 x
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Shear force at the base of the stem V = ( 6.04 + 55.03 2 ) 9 = 274.815 kN / m Allowable wide beam shear resistance of concrete, V ud V ud = 0.3 *fctd *1000* (1+50* 0.02) =0.3 *1.0 *1000* (1+50* 0.02) = 600kPa Then t b = V V ud = 274.815 600 = 0.458 m Take t b = 0.50m =50cm ii, Calculation of Vertical Dead Loads W 1 = 0.30*9.0*25 = 67.5kN/m =15 0 9m 0.80m 7m 2.35m 0.30m 0.50m 4.15m 4.15 tan15 0 =1.11m p= 20kN/m 2 W 4 W 2 W 1 W 6 W 5 W 3 W 7
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