e-m Ratio Previous

# e-m Ratio Previous - Date Grade Physics 211L Charge-to-Mass...

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Date:_____________ Physics 211L Charge-to-Mass Ratio of an Electron Name: Section number:1 Partner’s Name: Instructor: Sara Najem A- DATA: Number of turns in a coil: 72 D (m) 0.662 0.662 0.661 0.659 0.66 d (m) 0.328 0.33 0.331 0.329 0.33 I 1 (A) 0.44 0.45 0.46 0.45 0.45 Average diameter of the Helmholtz coils: 0.6608 ± 0.05 (m) Average separation of the coils: 0.3292 ± 0.05 (m) Average value of I 1 = 0.45 ± 0.01 (A) R(m) I 2 (A) I ( A) 1/R 2 ( y ) B ( T ) B 2 =x x 2 =B 4 e=y- x+ e 2 0.0325 3.27 2.82 946.75 0.00055 3.059E-07 9.358E-14 -42.264 1786.21 0.039 2.8 2.35 657.46 0.00046 2.124E-07 4.513E-14 -29.349 861.41 0.045 2.41 1.96 493.83 0.00038 1.477E-07 2.184E-14 16.062 257.99 0.0515 2.14 1.69 377.04 0.00033 1.099E-07 1.207E-14 21.836 476.82 0.0575 1.92 1.47 302.46 0.00029 8.313E-08 6.909E-15 33.715 1136.68 Sums 12.54 10.29 2777.53 0.00201 8.5903E- 07 1.796E-13 2.842E-13 4519.12 Plot 1/R 2 vs. B 2 and calculate, using linear regression, the slope of the line. Determine from the slope the value of e/m with its associated error. (Hint: it is best if you use EXCEL, or some other similar program, to fill your table) We get from the linear regression: α = 3*10 9 e/m = 2V α = 2*30* 3*10 9 = 1800*10 8 The error σ α 2 = 2 * 2 i e N N 1 Grade:

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∆=NΣx i 2 – (Σx i ) 2 = 5* 2 17 14 14 14 14 ) 7 10 * 8.5903 ( ) 10 * 9105969 . 6 10 * 207801 . 1 10 * 181529 . 2 10 * 511376 . 4 10 * 357481 . 9 ( =1.253223* 13 10
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