Solution Set 10

# Solution Set 10 - 10-1 (a) 0.97 Fc E f Vv Ff (260 GPa ) (Vf...

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10-1 (a) ( ) ( )( ) ( )( ) f f f m v f c c c m f V 1 GPa 8 . 2 V GPa 260 V 1 E V E 33 . 32 F 97 . 0 F F 97 . 0 F F - = - = = - = ; solve for V f = 0.258 (b) ( ) ( )( ) ( )( ) MPa 1069 258 . 0 MPa 4000 258 . 0 1 MPa 50 V V 1 f f f m c = + - = σ + - σ′ = σ * * 10-2 (a) ( )( ) ( )( ) 66 . 44 55 . 0 GPa 4 . 2 45 . 0 GPa 131 V E V E F F m m f f m f = = = (b) 978 . 0 F F 66 . 44 F 66 . 44 F F F F F m m m m f f c f + = + = F f = 0.978F c = 0.978(53,400 N) = 52,225 N F m = (1 – 0.978)(53,400 N) = 1,175 N (c) A f = A c V f = (480 mm 2 )(0.45) = 216 mm 2 = 216 × 10 -6 m 2 A m = A c V m = (480 mm 2 )(0.55) = 264 mm 2 = 264 × 10 -6 m 2 MPa 78 . 241 m N 10 78 . 241 m 10 216 N 225 , 52 A F 2 6 2 6 f f f = × = × = = σ - MPa 45 . 4 m N 10 45 . 4 m 10 264 N 175 , 1 A F 2 6 2 6 m m m = × = × = = σ (d) MPa 25 . 111 m N 10 25 . 111 m 10 480 N 400 , 53 A F 2 6 2 6 c c c = × = × = = σ - E c = E f V f + E m V m = (131 GPa)(0.45) + (2.4 GPa)(0.55) = 60.27 GPa 00185 . 0 MPa

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## This note was uploaded on 01/07/2012 for the course MECH 210 taught by Professor Hsu during the Fall '08 term at CSU Chico.

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Solution Set 10 - 10-1 (a) 0.97 Fc E f Vv Ff (260 GPa ) (Vf...

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