Unformatted text preview: So the E for electrolysis is actually:
Eapp = (Eanode + !ac + !aa) - (Ecathode + !cc + !ca)
!ac = concentration overpotential at anode
!aa = activation overpotential at anode
!cc = concentration overpotential at cathode
!ca = activation overpotential at cathode
This explains why many reactions do not proceed
as expected or will not occur at all. Can Pb2+ be quantitatively be separated from
Cu2+ by electrodeposition?
Assume that our solution starts with 0.1M of
each metal ion.
We’ll define quantitative as only 1 part in
10,000 cross contamination (99.99%)
Cu2+ + 2e = Cu
Pb2+ + 2e = Pb 0.0592
10-5 E = 0.337V
E = -0.126V 1
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This note was uploaded on 01/07/2012 for the course CHEM 290 taught by Professor Harvey during the Fall '08 term at SUNY Stony Brook.
- Fall '08