L9-page8 - where • It obviously gets much more difficult...

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8 Solving the differential equation for two layers and a source and sink Governing Equation 0 z V r V r 1 r V 2 2 2 2 = + + Boundary Conditions () solution Particular 0 = z 0, = r at z r 2 i V 4. continous is density current Normal z = z at z V 1 z V 1 3. continuous is Voltage z = z at V V 2. surface at current No 0 i 1. 2 1 2 2 1 interface 2 2 1 1 interface 2 1 0 z z + π ρ = ρ = ρ = = = a C 1 P 1 z int = h ρ 1 ρ 2 Layer Calculations • Can use for image theory for multiple boundaries. For two layer case:
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Unformatted text preview: where • It obviously gets much more difficult with more layers. ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ + π ρ = ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ + + + + + π ρ = ∑ ∞ = 1 n n n 1 n n 2 2 1 1 p r k 2 r 1 2 I .... r k 2 ..... r k 2 r k 2 r 1 2 I V ( ) 2 2 n nh 2 r r + = 1 2 1 2 k ρ + ρ ρ − ρ =...
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This note was uploaded on 01/07/2012 for the course PHYSICS 384 taught by Professor Wei during the Spring '09 term at SUNY Stony Brook.

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