# L8-page6 - 2 shell r 2 dr i A l i iR dV π ρ = ρ = =...

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6 Current Source on Surface Electric potential at distance away from current source on surface given as V(r)= ρ I/2 π r. How? Boundary conditions : 1)As r => , V => 0. 2) V is continuous across any boundary 3) Tangential E continuous across any boundary 4) Normal I continuous across any boundary. 5) Above leads to no vertical current crossing earth-air interface. Current Flow in a Homogeneous and Isotropic Medium
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Unformatted text preview: 2 shell r 2 dr i A l i iR dV π ρ = ρ = = Point Current Source: ( ) ( ) D 2 i D 1 1 1 2 i r 1 1 2 i r dr 2 i dV V D D 2 D D π ρ = ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ − ∞ − π ρ = − π ρ = π ρ = = ∞ ∞ ∞ ∫ ∫ Voltage decreases as the inverse of the distance from the current source. Shape of constant voltages are hemispheres for a single point source....
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## This note was uploaded on 01/07/2012 for the course PHYSICS 384 taught by Professor Wei during the Spring '09 term at SUNY Stony Brook.

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