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Split_00035 - 8.60 a dC i = dC i pv pl b g dC i = 20...

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8- 35 8.60 a. C C p v p l d i d i = = ⋅° 20 cal (mol C) ; C C R v v p v b g d i b g ⋅° = ⋅° 10 2 8 cal mol C cal (mol C) b. n 0 (mol N 2 ) n 0 (mol N 2 ) 3.00 [email protected] 93 o C, 1 atm n 2 [mol A(v)] 85 o C, P (atm) n 1 (mol A(l) n 3 [mol A(l)] 0.70 mL, 93 o C 85 o C, P (atm) n 0 273 93 0100 = + = 3.00 L 273 K 1 mol K 22.4 L STP mol N 2 b g b g . n A l 1 0 90 15 = = 70.0 mL g 1 mol mL 42 g mol . . b g Energy balance = = Δ U n U n U i i i i 0 0 out in ± ± c. References : N g C, 1 atm 2 b g b gb g , A l 85 ° Substance N in mol in cal mol in in out out 2 n U n U n A l n U A v n ± ± . . . . ± 010 39 8 010 0 15 160 0 20050 3 2 b g b g C A l , 93 ° b g and N C 2 g U C v , : ± 93 93 85 ° = b g b g C cal mol A v U A v , : ± , ( ) 85 20 90 85 20 000 10 85 90 20050 ° = + + = b g b g b g Δ U n n v v = =
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