Split_00037 - 8.61 (contd) Plot p (log scale) vs. 1 T...

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8- 37 8.61 (cont’d) Plot p (log scale) vs. 1 T (linear scale); straight line fit yields ln . p T = + 3770 17 28 K bg or pT 3196 10 3770 7 .e x p vi) p T T b b A −− =⇒ = = 760 1 17 28 760 3770 2824 10 31 mm Hg K 354 K Part v .l n . vii) Δ ΔΔ ± ± . ± , H R HH v vv = = A Part v K 3770 K J mol K J mol 3770 8 314 31300 b g b g (b) Basis: 3.5 L feed 273 K 1 mol s 510 K 22.4 STP mol s feed gas l = 00836 . Let A denote the drug 0.80 N 0.0836 mol/s @ 510 K 2 [mol A(v)/s] n 1 0.20 A [mol N /s] n 22 T (K), saturated with A (mols A( )/s), 90% of A in feed n 3 l T (K) Q (kW) . . . N balance: mol s mol N s 2 2 ² .. . n 2 0800 0 0836 0 0669 == b g 90% condensation: ² . . nA l 3 0 900 0 200 0 0836 0 01505 = b g b g mol s ² . . v 1 3 0100 0 200 0 0836 167 10 = × b
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