Split_00040 - 8.63(Contd S balance on mixing point 0.12...

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8- 40 8.63 (Cont’d) S balance on mixing point: 012 27273 0 45 172730 2 000 10 100% 405% 5 2 2 . . . . b gb g b gb g + = × = X X S (b) Draw system boundary for every balance to enclose freezer and mixing point (Inputs: fresh feed and recycle streams; output; slurry leaving freezer) Refs : S, H O 2 l b g at − ° 7 C substance 12% soln kg h 45% soln kJ kg H O s in in out out 2 ± ² ± ² ± ² m H m H m H 27273 108 172730 28 180000 0 20000 337 b g b g b g Solutions : ² . H T T b g b g = − − 4 00 7 kJ kg Ice : ² ² ² . H H T H m m = − ° ≈ − ° = − ⇒ − D Δ Δ C C kJ mol kJ kg Table B.1 b g b g 0 6 0095 337 E.B. ± ± ± ² ± ² . Q H m H m H c i i i i = = = × = − Δ out in kJ 1 h 1 kW h 3600 s 1 kJ s kW 1452 10 4030 7 8.64 a. B=n-butane, I=iso-butane, hf=heating fluid. ( ) . C p hf = 2 62 kJ / kg C o d i 24.5 kmol/h @ 10 o C, P (bar) 24.5 kmol/h @ 180 o C 0.35 kmol B(l)/h 0.35 kmol B(l)/h ±
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