Split_00041 - 8.64(contd References B(l 10oC I(l 10oC substance nin mol h H in kJ mol b B(l B(v I(l I(v g b 8575-15925 z z b g nout mol h 0-0

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8- 41 8.64 (cont’d) References: B(l, 10 o C), I(l, 10 o C) substance ± n in mol / h bg ² H in kJ / mol ± n out mol / h ² H out kJ / mol B (l) 8575 0 -- -- B (v) -- -- 8575 42.21 I (l) 15925 0 -- -- I (v) -- -- 15925 41.01 ²² . . .. HH C C Hn H n H out v p out v p ii out in di d i d i BB B II I kJ / mol kJ / mol =+ = = =−= z z ∑∑ Δ Δ Δ 10 180 10 180 42 21 4101 8575 42 21 15825 4101 Δ ± . H 1015 10 6 kJ / h c. Qm 1015 10 2 62 215 45 6 . ± . kJ / h = kJ / kg C C hf oo ± m hf kg / h = 2280 d. 2540 2 62 215 45 1131 10 6 kg / h kJ / kg C C kJ / h ⋅− = × Heat transfer rate kJ / h −× = × 1131 10 1015 10 116 10 66 5 ... e. The heat loss leads to a pumping cost for the additional heating fluid and a greater heating cost to raise the additional fluid back to 215 o C. f. Adding the insulation reduces the costs given in part (e). The insulation is probably preferable since it is a one-time cost and the other costs continue as long as the process runs. The final decision would depend on how long it would take for
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This note was uploaded on 01/07/2012 for the course CH E 210 at Pennsylvania State University, University Park.

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