Split_00046 - 8.67 Basis 2500 kmol product 1 kmol...

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8- 46 8.67 Basis: 2500 kmol product 1 kmol condensate h .25 kmol product kmol h fed to condenser = 10 000 , 1090 kmol/h C H ( ) v 38 7520 kmol/h -C H ( ) v 41 0 i 1390 kmol/h -C H ( ) v 0 n saturated vapor at T f , P P (mm Hg) m 1 , (kg/h) at T 1 1090 kmol/h C H ( ) l 7520 kmol/h -C H ( ) l 0 i 1390 kmol/h -C H ( ) l 0 n T out m 1 (kg/h) at T 2 2 . . (a) Refrigerant: T o out C = 0 , TT o 12 6 == C . Antoine constants A B C CH 7.58163 1133.65 283.26 i 0 6.78866 899.617 241.942 n 0 6.82485 943.453 239.711 Calculate for out bubble pt. PT T = () ( ) ( )( ) * 0 C 0.109 3797 mm Hg 0.752 1176 mm Hg 0.139 775 mm Hg 1406 mm Hg ii i Px p P = + + ⇒= Dew pt. dp * 10 i ff i if y f T P pT =⇒ = = trial & error to find o 5.00 C Refs: l bg , C H 0 l at 0 ° C, Refrigerant @ –6 ° C A s s u m e : Δ ± HT vb , Table B.1
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