Split_00060 - d i 8.85 2 mol H 2SO 4 = 0.30 2.00 + nH 2 O...

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8-60 8.85 2 mol H SO mol H O mol H O mol H SO 2 4 HO 2 2 24 22 =+ = = = 030 200 467 2 233 .. . . . nn r di a. For this closed constant pressure system, QH n H r s == ° = = =− ΔΔ HSO C, 2 mol H SO kJ mol H SO kJ ± . . . 25 2 33 44 28 886 bg b. m solution 2 2 2 mol H SO 98.08 g H SO mol 4.67 mol H O 18.0 g H O mol g = 280 2 . HnH r m C d T sp T =⇒ ° = + = z 02 5 2 3 30 25 ± . +− ° ⋅° =⇒ = ° 88 6 280 6 150 25 08 7 . . kJ + g 3.3 J C 1 kJ g C 1000 J C b g T T 8.86 a. Basis: 1 L product solution 1.12 10 g L g solution 3 ej = 1120 1 L 8 mol HCl 36.47 g HCl Lm o l H C l g HCl = 292 46.0 mol H 2 O(l, 25°C) 8.0 mol HCl(g , 20°C, 790 mm Hg) 1 L HCl (aq) 1120 g 292 g 828 g H O 2 −= 828 g H O mol
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