Split_00002 - 9.2 (cont'd) d. Heat Output = 1.53105 kW. The...

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9- 2 d. e. Heat Output = 1.53 × 10 5 kW. The reactor pressure is low enough to have a negligible effect on enthalpy. C H g O g) 9CO (g) +10H O(l) (1) kJ / mol C H l O g) 9CO (g) +10H O(l) (2) kJ / mol (2) C H l C H g C H C) kJ / mol kJ / mol) = 47 kJ / mol 92 2 2 r o 2 2 r o 99 v o 9 20 20 20 20 20 14 6171 14 6124 1 25 6124 6171 () ( ± ( ± ( ) ± (, ( +→ =− −⇒ −− Δ Δ Δ H H H D Yes. Pure n-nonane can only exist as vapor at 1 atm above 150.6 ° C, but in a mixture of gases, it can exist as a vapor at lower temperatures. 9.3 9.4 a. b. c. a. b. Exothermic. The reactor will have to be cooled to keep the temperature constant. The temperature would increase under adiabatic conditions. The energy required to break the reactant bonds is less than the energy released when the product bonds are formed. CH g O g CO g HOg CH l HOl B tulb-mo l e 61 4 2 r o 4 2 r o bg bg bg b g bg b g +→+ = = = × 19 2 67 1 19 2 2 1 7 9 1 1 0 22 2 6 Δ ΔΔ ± ? ±± . H HH C H g C H l Btu lb - mole 4 4 v CH 21 4 ej →= = 31 3 5 5 0 3 , B tulb -m o l e v HO 2 b g b g = 41 8 9 3 4 4 , 123 7 4 7 1 6 7 2 1 0 4 6 bg bg bg =++ × = + + = × Hess's law Btu lb - mole ΔΔΔ Δ ±±± ± . HHH H ² / ² . mn =⇒ = 120 375 lb lb M= 3 2 . 0 O 2 m s - mole / s.
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