Split_00005 - 9.10 a bg C8 H 18 l bg bg 25 O 2(g 8CO 2 g 9H...

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9-5 9.10 a. b. c. C H l 25 2 O g) 8CO g 9H O g kJ / mol 8 18 2 2 2 r o b g b g b g + + = − ( ± Δ H 4850 When 1 g-mole of C 8 H 18 (l) and 12.5 g-moles of O 2 (g) at 25 ° C and 1 atm react to form 8 g-moles of CO 2 (g) and 9 g-moles of H 2 O(g), the change in enthalpy equals -4850 kJ. Energy balance on reaction system (not including heated water): Δ Δ Δ Δ E E W Q U n U k p , , ± mol C H consumed kJ mol 8 18 c o = = = 0 b g b g ( . C p H O(l) ) from Table B.2 kJ / mol. C 2 = × 754 10 3 D = = × ° × = Q m C T H O p H O(l) 2 2 1.00 kg 1 mol 75.4 10 kJ 21.34 C 18.0 10 kg mol. C kJ ( ) . Δ 3 3 89 4 D Q U U U = ⇒ − = = − Δ Δ Δ 89 4 5079 . ± ± kJ 2.01 g C H consumed 1 mol C H (kJ) 114.2 g 1 mol C H kJ mol 8 18 8 18 c o 8 18 c o Δ Δ ± ± . H U RT i i c o c o gaseous products gaseous reactants 3 kJ mol 8.314 J 1 kJ 298 K mol K 10 J = + L N M M M M
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