Split_00022 - 9.22 (cont'd) Plan of attack: % excess air n0...

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9- 22 Plan of attack: excess air Ideal gas equation of state 13% C H CHO formation 0.5% CO formation E.B. on reactor C balance E.B. on jacket H balance Scale , by actual / basis O balance 65 2 % ,, ± ⇒⇒ nV nQ nm V Q m n n n p w pw 00 3 4 1 50 5 5 2 bg 100% excess air: n 0 11 200 = + = 100 lb - moles C H CH 1 mol O reqd mole O fed 1 mole C H CH lb - moles O 65 3 2 2 2 2 N feed & output lb - moles N lb - moles N 22 2 b g == 376 200 752 . 3 3 3 3 3 100 lb-moles C H CH 0.13 mole C H CH react 1 mole C H CHO formed 13% C H CHO 1 mole C H CH fed 1 mole C H CH react = 13 lb-moles C H CHO n →⇒ = 0.5% CO 100 0.005 lb - moles C H CH react 7 moles CO 1 mole C H CH lb - moles CO 2 2 2 = = n 4 35 b g . C balance: 100 7 7 13 7 3 5 1 86 5 af a f a f a f a f 6 5 3 mol C mole C 7 H 8 lb - moles C lb - moles C H CH B =+ + = nn .. H balance: 100 8 865 8 13 6 2 150 55 b g b g b g b g b g lb - moles H lb - moles H O v
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This note was uploaded on 01/07/2012 for the course CH E 210H at Pennsylvania State University, University Park.

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