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cstut9 - To shift more than one step just include a for...

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Returns the index(position in the list) of the element just larger than the input value If need just smaller, return i-1; To return the exact value, add If (i < numElem && list[i] == value) return i; else return -1; Starting from location list[start], shifts “end” elements one step to the right
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Unformatted text preview: To shift more than one step, just include a for loop: for shifting 3 steps: for (j=1, j<=3, j++) Using findIndex and shiftRight to sort the array....
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