cs345-4

cs345-4 - 1 Extended Conjunctive Queries Unions Arithmetic...

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Unformatted text preview: 1 Extended Conjunctive Queries Unions Arithmetic Negation 2 Containment of Unions of CQs Theorem: P 1 P k Q 1 n if and only if for each P i there is some j such that P . Proof (if): Obvious. 3 Proof of Only-If Assume P 1 P k Q 1 n . Let D be the canonical (frozen) DB for i . Since the containment holds, and P (D) includes the frozen head of P , there must be some Q j such that Q (D) also includes the frozen head of P . Thus, P . 4 CQ Contained in Datalog Program Let Q be a CQ and P a Datalog program. Each returns a relation for each EDB database D, so it makes sense to ask if Q P. That is, Q(D) P(D) for all D. 5 The Containment Test Let D be the canonical DB for Q. Compute P(D), and test if it contains the frozen head of Q. If so, Q P ; if not, D is a counterexample. 6 Example Q : p(X,Y) :- a(X,Z) & a(Z,W) & a(W,Y) P : p(X,Y) :- a(X,Y) p(X,Y) :- p(X,Z) & p(Z,Y) Intuitively: Q = paths of length 3; P = all paths. Frozen Q : D = {a(x,z), a(z,w), a(w,y)}. 7 Example --- Continued D = {a(x,z), a(z,w), a(w,y)} P : p(X,Y) :- a(X,Y) p(X,Y) :- p(X,Z) & p(Z,Y) Infer by first rule: p(x,z), p(z,w), p(w,y). Infer by second rule: p(x,w), p(z,y), p(x,y). Frozen head of Q, so Q P. 8 Other Containments It is doubly exponential to tell if a Datalog program is contained in a CQ....
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cs345-4 - 1 Extended Conjunctive Queries Unions Arithmetic...

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