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Unformatted text preview: M = ( 1 2 0 1 ). Then the assertion follows from (5.10). Now we argue by induction on | | + | | . If | | > | | , using that ( z, + 2) = ( z ; ), we substitute 2 in (5.16) to obtain that the assertion is true for M = 2 2 . Since we can decrease | 2 | in this way, the assertion will follow by induction. Note that we used that | 2 | is not equal to | | or | | because ( , ) = 1 and is even. Now, if | | < | | , we use the substitution -1 / . Using (5.13) we see that the asssertion for M follows from the assertion fo M = - - . This reduces again to the case | | > | | ....
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This note was uploaded on 01/08/2012 for the course MATH 300 taught by Professor Ontonkong during the Fall '09 term at SUNY Stony Brook.
- Fall '09