# Split_00037 - 9.29 (cont'd) Energy Balance : H = n H - n H...

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9- 37 Energy Balance : kg steam h out in Δ Hn H m m ii b b =−= ⇒− × = ⇒= ∑∑ ±± .. . 0 27261 1257 4 92 10 0 1892 6 bg 9.30 a. b. CH HC l CHC l 24 25 +→ Basis: 1600 kg C H Cl l 10 g 1 mol h 1 kg 64.52 g mol h C H Cl 3 = 24800 (mol HCl( )/h) reactor n 1 g 0°C A (mol/h) at 0°C n 2 0.93 C H B 0.07 C H 26 (mol HCl( )/h) n 3 g (mol C H ( )/h) n 4 g (mol C H ( )/h) n 5 g (mol C H Cl( )/h) n 6 g 50°C condenser n 6 ( – 24,800) (mol C H Cl( )/h) l 0°C n (mol HCl( )/h) n 3 g (mol C H ( )/h) n 4 g (mol C H ( )/h) n 5 g C 0°C 24,800 mol C H Cl( )/h l 2 5 D Product composition data: nn 31 0015 1 = . n 42 2 0 015 093 001395 2 == . b g 52 007 3 = . Overall Cl balance : n n 1 3 1 24800 1 4 mol HCl h 1 mol Cl 1 mol HCl b g bg b g =+ Solve (4) simultaneously with (1) mol h kmol HCl fed / h = n 1 25180 2518 . n 3 378 = mol HCl g h
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## This note was uploaded on 01/07/2012 for the course CH E 210H at Pennsylvania State University, University Park.

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