# Split_00041 - 9.32(cont'd 3130 Btu lb mole b g CO bg,1830 Fg H = H(1830 F 20,880 Btu lb mole CObg,1830 Fg H = H(1830 F 13,280 Btu lb mole 0.24 Btu

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9- 41 b. CO g F 2 400 ,: ° bg ±± ( HH =⇒ CO Table B.9 2 F) Btu lb - mole 400 3130 D CO g, F 2 1830 ° : ( CO Table B.9 2 F) Btu lb - mole 1830 20,880 D CO g, F 1830 ° ( CO Table B.9 F) Btu lb - mole 1830 13,280 D Solid 1830 ° F ± . H = −° = 024 1830 77 420 Btu F lb F Btu lb m m D Mass of solids (emerging) = += 7001 16 100 84 . x x lb - moles C 12.0 lb 1 lb - mole lb lb m mm substance (lb moles) (Btu lb - mole) (lb moles) (Btu lb-mole) CO 7.00 3130 CO solid (lb (Btu lb (lb (Btu lb in in out out 2 m m n H n H x x x −− ., )) ) ) 7 00 1 20 890 14 0 13 280 100 0 100 84 420 Extent of reaction: n n lb- moles) = 7.0 CO CO o CO = + = () . ( ν ξ 14 0 2 xx Energy balance: QH H n H n H ii == + ΔΔ r o out in ± 585 7 00 1 20 880 14 0 13 100 84 420 7 00 3130 0 801 801% ,900 . , . ,280 . .. Btu 7.0 (lb - moles) 74,210 Btu lb - mole conversion =+ ++ E x
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## This note was uploaded on 01/07/2012 for the course CH E 210H at Pennsylvania State University, University Park.

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