Split_00047 - 9.35(cont'd T = bg 145600 zb T 1273 9.419...

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9- 47 c. d. φ T TdT TT T bg ej = −+ + × + z z z 145600 9 419 01147 26 90 4167 10 1135 01392 1273 3 1273 1273 .. . . T = ++ −− 3052 36 2 0 05943 127240 113 0 0696 2 2 K KT K T p p p p 1 1 11 1 1 0 12 + F H G I K J = + + F H G I K J + == φφ ψ T given by expression of Part b. p given by Eq. (1) P T f Kp Phi Psi (atm) (K) (atm) 0.01 794 0.518 0.0037 0.93152 -0.0001115 0.05 847.4 0.47 0.0141 1.12964 -0.0002618 0.1 872.3 0.446 0.025 1.24028 0.00097743 0.5 932.8 0.388 0.0886 1.57826 3.41E-05 1 960.3 0.36 0.1492 1.77566 4.69E-05 5 1026 0.292 0.4646 2.42913 -2.57E-05
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This note was uploaded on 01/07/2012 for the course CH E 210H at Penn State.

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