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Split_00053 - 9.39 Mass of H 2 SO 4 = Mass of solution = 3...

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9- 53 9.39 Mass of H SO m 10 L 1 mol H SO 1 m L mol H SO 98.02 g 1 mol g H SO Mass of solution m 10 L 10 mL 1.064 g 1 m L 1 mL g solution 2 4 3 3 2 4 3 2 4 2 4 3 3 3 3 = = F H G I K J = × = = × 3 3000 2 941 10 3 3192 10 5 6 . . = × × = × Moles of H O g H O( 1 mol 18.02 g mol H O 2 2 2 ( . . ) ) . 3192 10 2 941 10 161 10 6 5 5 n mol H O mol H SO mol H O mol H SO mol H O mol H SO 2 2 4 2 2 4 2 2 4 F H G I K J = × = 161 10 3000 536 5 . . Δ Δ Δ ± ± ± . . . , . ., . H H H f H SO aq. r f o H SO l s H SO aq r 2 2 Table B.1 2 Table B.11 kJ mol kJ mol e j e j e j b g b g b g b g 4 4 4 53 6 53 6 81132 7339 884 7 = A = A = + = − = − H = × (3000 mol H SO )(-884.7 kJ / mol H SO ) = -2.65 10 kJ 2 4 2 4 6 9.40 HCl (aq): Δ Δ Δ ± ± ± . . . H H H f o f o HCl g s o Tables B.1, B11 kJ mol = + = = − e j e j b g 92 31 7514 167 45 NaOH (aq): Δ Δ Δ ± ± ± . . . H H H f o f o NaOH s s o Tables B1, B.11 kJ mol = + = = − B e j e j b g 426 6 42 89 469 49 NaCl (aq): Δ Δ Δ ± ± ± . . . H H H f o f o NaCl s s o Table B.1 Given kJ mol = + = − + = − B B e j e j b g 4110 4 87 4061 HCl aq NaOH aq NaCl aq H O l 2 b g b g b g b g + + Δ ± . . . . . H r o kJ mol = − − − − − = − 4061 28584 167 45 469 49 550 b g b g HCl g NaOH s NaCl s H O l 2 b g b g b g b g + + Δ Δ Δ ± ± ± . . . . . H v H v H i i r o f o products f o reactants kJ mol
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