Split_00064 - 9.54 (cont'd) b. Energy balance on vaporizer:...

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9- 64 b. Energy balance on vaporizer: QH n H C dT H C dT pl v pv 1 14 0 3 3 == = + + L N M M M O Q P P P = A A A zz ΔΔ Δ ± ± . mol kJ mol kJ Table B.2 25 64.7 Table B.1 Table B.2 64.7 100 References : CH OH v , N (g), O (g), CO (g), H O l at 25 C 32 2 2 2 a f a f ° Substance (mol) (kJ / mol) (mol) (kJ / mol) CH OH 1.00 N O CO HO in in out out 3 2 2 2 n H n H ±± . .. . . . . 3603 1685 2187 8118 4482 2235 298 8470 100 11578 200 5358 2 −− HT H i a f = for N , O , CO (Table B.8) 22 2 =+ Δ HH vi 25 D C for H O v (Eq. 9.6 -2a on p. 462, Table B.8) 2 di a f = z CdT p T 25 for CH OH v (Table B.2) 3 a f (Note: HOl 2 bg was chosen as the reference state since the given value of Δ ± H c o presumes liquid water as the product.) Extent of reaction : () nn out in CH OH CH OH CH OH 33 3 mol mol = + = −⇒= ν ξ 01 1 Energy balance on reactor: Q H nH ii 2 ξΔ ± c o out in =− + + 1 764 0 1685 8118 4 482 2 235
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